Question

Phân tích đa thức thành nhân tử
a)2x²-8x+8
b)4x-4y+x²-y²
c)-6x+8+x²

Answer 1

a) = 2(x-2)^2

b) = 4(x - y) + (x - y)(x + y)

= (x - y)(x + y + 4)

c) = (x - 2)(x - 4)

Answer 2

\(2\left(x-2\right)^2\)

\(\left(4+x+y\right)\left(x-y\right)\)

 

Answer 3

a: \(2x^2-8x+8=2\left(x-2\right)^2\)

b: \(4x-4y+x^2-y^2\)

\(=4\left(x-y\right)+\left(x-y\right)\left(x+y\right)\)

\(=\left(x-y\right)\left(4+x+y\right)\)

c: \(x^2-6x+8=\left(x-2\right)\left(x-4\right)\)