c: \(9^{15}=3^{30}\)
\(27^{10}=3^{30}\)
Do đó: \(9^{15}=27^{10}\)
d: \(2^{333}=8^{111}\)
\(3^{222}=9^{111}\)
Do đó: \(2^{333}< 3^{222}\)
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c)
\(9^{15}=\left(3^2\right)^{15}=3^{30}\)
\(27^{10}=\left(3^3\right)^{10}=3^{30}\)
=> \(9^{15}=27^{10}\)
d)
\(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
=> \(2^{333}< 3^{222}\)
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