Question

Mình cần gấp. giúp mình nhá

Cho a,b,c>0

\(\left(1+\frac{a}{b}\right).\left(1+\frac{b}{c}\right).\left(1+\frac{a}{c}\right)\ge8\)

 

Answer 1

Ta có \(\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)=\frac{\left(a+b\right)\left(b+c\right)\left(c+a\right)}{abc}\)

Áp dụng bđt Cauchy, ta có : \(a+b\ge2\sqrt{ab}\) ; \(b+c\ge2\sqrt{bc}\); \(c+a\ge2\sqrt{ac}\)

\(\Rightarrow\left(a+b\right)\left(b+c\right)\left(c+a\right)\ge8abc\)

\(\Rightarrow\frac{\left(a+b\right)\left(b+c\right)\left(c+a\right)}{abc}\ge8\)

Vậy \(\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\ge8\)(đpcm)

Đề của bạn chưa đúng nhé :)