Question

lx-\(\dfrac{1}{3}\)l - 0,25 = \(\dfrac{3}{4}\)

Answer 1

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=1\\x-\dfrac{1}{3}=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{2}{3}\end{matrix}\right.\)

Answer 2

\(\left|x-\dfrac{1}{3}\right|-0,25=\dfrac{3}{4}\)

\(\left|x-\dfrac{1}{3}\right|-\dfrac{1}{4}=\dfrac{3}{4}\)

\(\left|x-\dfrac{1}{3}\right|=\dfrac{3}{4}+\dfrac{1}{4}=1\)

\(\text{Vậy }x-\dfrac{1}{3}=1\)

       \(x\)         \(=1+\dfrac{1}{3}=\dfrac{4}{3}\)

\(\text{hoặc }x-\dfrac{1}{3}=-1\)

       \(x\)          \(=\left(-1\right)+\dfrac{1}{3}=\dfrac{-2}{3}\)

\(\Rightarrow x\in\left\{\dfrac{4}{3};\left(\dfrac{-2}{3}\right)\right\}\)