\(\left\{{}\begin{matrix}2x-5y=3\\6x-15y=10\end{matrix}\right.\)
Vì \(\dfrac{2}{6}=\dfrac{-5}{-15}\ne\dfrac{3}{10}\)
nên hệ phương trình vô nghiệm
\(\left\{{}\begin{matrix}5x+7y=11\\10x+14y=22\end{matrix}\right.\)
Vì \(\dfrac{5}{10}=\dfrac{7}{14}=\dfrac{11}{22}=\dfrac{1}{2}\)
nên hệ phương trình có vô số nghiệm
Giải các hệ phương trình sau bằng phương pháp thế:
a)\(\left\{{}\begin{matrix}3x-2y=11\\4x-5y=3\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{x}{2}-\dfrac{y}{3}=1\\5x-8y=3\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}3x+5y=1\\2x-y=-8\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{x}{y}=\dfrac{2}{3}\\x+y-10=0\end{matrix}\right.\)
\(\left\{{}\begin{matrix}3x+y=3\\2x-y=7\end{matrix}\right.\)
..
\(\left\{{}\begin{matrix}2x+5y=8\\2x-3y=0\end{matrix}\right.\)
..
\(\left\{{}\begin{matrix}4x+3y=6\\2x+y=4\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2x+5y=-2\\x-y=6\end{matrix}\right.\)
\(\left\{{}\begin{matrix}3x+y=-3\\2x+5y=-6\end{matrix}\right.\)
giải hệ
\(\left\{{}\begin{matrix}4x-2y=3\\6x-3y=5\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2x+3y=5\\4x+6y=10\end{matrix}\right.\)
Giải các hệ phương trình sau:
a) \(\left\{{}\begin{matrix}2x+5y=5\\3x-5y=-30\end{matrix}\right.\) b) \(\left\{{}\begin{matrix}4x-3y=-5\\3x+2y=-8\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}3x+3y=9\\4x-2y=-2\end{matrix}\right.\) d) \(\left\{{}\begin{matrix}5x-4y=32\\6x+2y=18\end{matrix}\right.\)
e) \(\left\{{}\begin{matrix}2x-3y+5=0\\3x+5y-21=0\end{matrix}\right.\) f) \(\left\{{}\begin{matrix}x-y\sqrt{2}=0\\2x\sqrt{2}+y=5\end{matrix}\right.\)
g) \(\left\{{}\begin{matrix}5x+4y=-3\\3x+2y=11\end{matrix}\right.\) h) \(\left\{{}\begin{matrix}2x-4y=12\\5x+3y=17\end{matrix}\right.\)
giải hệ phương trình
1)\(\left\{{}\begin{matrix}3x+4y=11\\2x-y=-11\end{matrix}\right.\) 2)\(\left\{{}\begin{matrix}3x+2y=0\\2x+y=-1\end{matrix}\right.\) 3)\(\left\{{}\begin{matrix}3x+\dfrac{5}{2}y=9\\2x+\dfrac{1}{3}y=2\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}-x+3y=16\\2x+y=3\end{matrix}\right.\) 5)\(\left\{{}\begin{matrix}\dfrac{-3}{x-y}+\dfrac{5}{2x+y}=-2\\\dfrac{4}{x-y}-\dfrac{10}{2x+y}=2\end{matrix}\right.\) 6)\(\left\{{}\begin{matrix}\dfrac{1}{x}-\dfrac{1}{y}=1\\\dfrac{3}{x}+\dfrac{4}{y}=5\end{matrix}\right.\)
\(\left\{{}\begin{matrix}6x^2y+2y^3+35=0\\5x^2+5y^2+2xy+5x+13y=0\end{matrix}\right.\)
Giải hệ pt sau = phương pháp thế:
a, \(\left\{{}\begin{matrix}\dfrac{x}{2}-\dfrac{y}{3}=1\\5x-8y=3\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}3x+2y=2\\6x-3y=18\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\dfrac{3x}{4}+\dfrac{7y}{3}=41\\\dfrac{5x}{2}-\dfrac{3y}{5}=11\end{matrix}\right.\)
