Question

\(\left(3x-\dfrac{1}{3}\right)^2=\dfrac{4}{49}\)

Answer 1

\(\left(3x-\dfrac{1}{3}\right)^2=\dfrac{4}{49}\)

\(\left(3x-\dfrac{1}{3}\right)^2=\left(\dfrac{2}{7}\right)^2\) hoặc \(\left(3x-\dfrac{1}{3}\right)^2=\left(\dfrac{-2}{7}\right)^2\)

\(3x-\dfrac{1}{3}=\dfrac{2}{7}\) hoặc \(3x-\dfrac{1}{3}=\dfrac{-2}{7}\)

*) \(3x-\dfrac{1}{3}=\dfrac{2}{7}\)

\(3x=\dfrac{2}{7}+\dfrac{1}{3}\)

\(3x=\dfrac{13}{21}\)

\(x=\dfrac{13}{21}:3\)

\(x=\dfrac{13}{63}\)

*) \(3x-\dfrac{1}{3}=\dfrac{-2}{7}\)

\(3x=\dfrac{-2}{7}+\dfrac{1}{3}\)

\(3x=\dfrac{1}{21}\)

\(x=\dfrac{1}{21}:3\)

\(x=\dfrac{1}{63}\)

Vậy \(x=\dfrac{1}{63}\); \(x=\dfrac{13}{63}\)