Question

\(\left(3\frac{1}{2}-x\right).1\frac{1}{4}=-1\frac{1}{20}\)

Answer 1

\(\left(3\frac{1}{2}-x\right).1\frac{1}{4}=-1\frac{1}{20}\)
\(\left(3\frac{1}{2}-x\right).\frac{5}{4}=\frac{-21}{20}\)
(\(\frac{7}{2}\)-x)        =\(\frac{-21}{20}:\frac{5}{4}\)
\(\frac{7}{2}\)-x           =\(\frac{-21}{20}.\frac{4}{5}\)
\(\frac{7}{2}\)-x        =\(\frac{-21}{25}\)
-x             =\(\frac{-42}{50}-\frac{175}{50}\)
-x             -\(\frac{-217}{50}\)
x=\(\frac{217}{50}\)=4\(\frac{17}{50}\)

Answer 2

(3 1/2 - x). 1 1/4 = -1 1/20

(7/2 - x). 5/4 = -21/20

7/2 - x = -21/20 : 5/4

7/2 - x = -21/25

x= 7/2-(-21/25)

x= 217/50