Question

Khử hoàn toàn 16,2g ZnO bằng khí H2.Tính m chất rắn thu đc sau phản ứng?

Answer 1

\(pthh:ZnO+H_2\overset{t^o}{--->}Zn+H_2O\)

Ta có: \(n_{ZnO}=\dfrac{16,2}{81}=0,2\left(mol\right)\)

Theo pt: \(n_{Zn}=n_{ZnO}=0,2\left(mol\right)\)

\(\Rightarrow m_{Zn}=0,2.65=13\left(g\right)\)

Answer 2

\(ZnO+H_2\rightarrow Zn+H_2O\)

\(n_{ZnO}=\dfrac{16.2}{81}=0.2\left(mol\right)=n_{Zn}\)

\(m_{Zn}=0.2\cdot65=13\left(g\right)\)