\(a,\left(x+3\right)^2\)
\(=x^2+2\cdot x\cdot3+3^2\)
\(=x^2+6x+9\)
\(b,\left(x-\dfrac{1}{3}\right)^2\)
\(=x^2-2\cdot x\cdot\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2\)
\(=x^2-\dfrac{2}{3}x+\dfrac{1}{9}\)
#\(Toru\)
a: (x+3)^2=x^2+6x+9
b: (x-1/3)^2=x^2-2/3x+1/9