\(\Leftrightarrow\dfrac{3\left(x-5\right)+12\left(1-2x\right)}{12}=\dfrac{4x-2\left(2-x\right)}{12}\)
\(\Leftrightarrow3\left(x-5\right)+12\left(1-2x\right)=4x-2\left(2-x\right)\)
\(\Leftrightarrow3x-15+12-24x=4x-4+2x\)
\(\Leftrightarrow-27x=-1\)
\(\Leftrightarrow x=\dfrac{1}{27}\)


