Question

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Answer 1

a: \(\Leftrightarrow\left(x-3\right)\left(2x+1-x-2\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)

hay \(x\in\left\{3;1\right\}\)

b: \(\Leftrightarrow x^2+x+1+2x^2-2x=3x^2\)

=>1-x=0

hay x=1(loại)

c: \(\Leftrightarrow3x^2+5x-3x-5=0\)

\(\Leftrightarrow\left(3x+5\right)\left(x-1\right)=0\)

hay \(x\in\left\{-\dfrac{5}{3};1\right\}\)