Question

Help

Answer 1

\(\dfrac{7\sqrt{3}-\sqrt{6}}{7-\sqrt{2}}+\dfrac{13}{4+\sqrt{3}}-3\sqrt{\dfrac{1}{3}}=\dfrac{\sqrt{3}\left(7-\sqrt{2}\right)}{7-\sqrt{2}}+\dfrac{13\left(4-\sqrt{3}\right)}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}-\sqrt{3}\)

\(=\sqrt{3}+\dfrac{13\left(4-\sqrt{3}\right)}{16-3}-\sqrt{3}\)

\(=\dfrac{13\left(4-\sqrt{3}\right)}{13}=4-\sqrt{3}\)