\(12+3.\left[39-\left(5-2\right)^2\right]\\ =12+3.\left[39-3^2\right]\\ =12+3.\left[39-9\right]\\ =12+3.30\\ =12+90\\ =102\)
\(100-\left[50+\left(9-4\right)^2\right]=100-\left(50+5^2\right)=100-\left(50+25\right)=100-75=25\)
\(12+3\left[39-\left(5-2\right)^2\right]=12+3\left(39-3^2\right)=12+3\left(39-9\right)=12+3.30=12+90=102\)
\(100-\left[50+\left(9-4\right)^2\right]\)
\(=100-\left[50+5^2\right]\)
\(=100-\left[50+25\right]\)
\(=100-75\)
\(=25\)
\(12+3\left[39-\left(5-2\right)^2\right]\)
\(=12+3\left[39-3^2\right]\)
\(=12+3\left[39-9\right]\)
\(=12+3\cdot30\)
\(=12+90\)
\(=102\)
2) 100 - [ 50 + ( 9 - 4 )2 ] 4) 12 + 3. [ 39 - ( 5 - 2 )2 ]
= 100 - [ 50 + 25 ] = 12 + 3. [ 39 - 9 ]
= 100 - 75 = 12 + 3. 30
= 25 = 12 + 90
= 102