Question

giúp mk nha khẩn cấp 

Answer 1

\(\dfrac{x^2-4x}{3x-6}+\dfrac{4}{3x-6}\)

\(=\dfrac{x^2-4x+4}{3x-6}\)

\(=\dfrac{\left(x-2\right)^2}{3\left(x-2\right)}=\dfrac{x-2}{3}\)

Answer 2

`[x^2-4x]/[3x-6]+4/[3x-6]`          `ĐK: x \ne 2`

`=[x^2-4x+4]/[3x-6]`

`=[(x-2)^2]/[3(x-2)]`

`=[x-2]/3`

Answer 3

  

Answer 4

`(x^2-4x)/(3x-6) + 4/(3x-6)`

`=(x^2 -4x +4)/(3x-6)`

`= ((x-2)^2)/(3x-6)`

`=  ((x-2)^2)/(3(x-2))`

`= (x-2)/3`