Question

giúp mk nha khẩn cấp huhu

 

Answer 1

1: ĐKXĐ: x<>-3; x<>2

2: \(D=\dfrac{x^2-4-5-x-3}{\left(x-2\right)\left(x+3\right)}=\dfrac{\left(x-4\right)\left(x+3\right)}{\left(x-2\right)\left(x+3\right)}=\dfrac{x-4}{x-2}\)

3: x^2-9=0

=>x=3(nhận) hoặc x=-3(loại)

Khi x=3 thì \(D=\dfrac{3-4}{3-2}=-1\)

4: Để D=-3/4 thì \(\dfrac{x-4}{x-2}=\dfrac{-3}{4}\)

=>4x-16=-3x+6

=>7x=22

=>x=22/7