`a)[3xx2xx8]/[4xx5xx6xx7]`
`=[3xx2xx4xx2]/[4xx5xx3xx2xx7]`
`=2/[5xx7]=2/35`
`b)[36xx22xx51]/[11xx17xx72]`
`=[9xx4xx11xx2xx17xx3]/[11xx17xx9xx4xx2]`
`=3`
\(\dfrac{3\times2\times2\times2\times2}{2\times2\times5\times2\times3\times7}=\dfrac{2}{35}\)
a) \(\dfrac{3.2.8}{4.5.6.7}=\dfrac{1.1.4}{2.5.2.7}=\dfrac{2}{35}\)
b) \(\dfrac{36.22.51}{11.17.72}=\dfrac{1.2.3}{1.1.2}=\dfrac{6}{2}=3\)
a) \(\dfrac{3\times2\times4\times2}{2\times2\times5\times3\times2\times7}=\dfrac{4}{70}=\dfrac{2}{35}\)
b) \(\dfrac{4\times9\times11\times2\times17\times3}{11\times17\times9\times8}=\dfrac{24}{8}=3\)