Question

giúp mình câu này với ạ

Answer 1

\(=\dfrac{\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{3}-\sqrt{2}}-\dfrac{\sqrt{6}\left(\sqrt{5}-\sqrt{3}\right)}{2\left(\sqrt{5}-\sqrt{3}\right)}=\dfrac{\sqrt{6}}{1}-\dfrac{\sqrt{6}}{2}=\dfrac{2\sqrt{6}-\sqrt{6}}{2}=\dfrac{\sqrt{6}}{2}\)

Answer 2

`= (sqrt 18 - sqrt 12)/(sqrt 3 - sqrt 2) - (sqrt 30 - sqrt 18)/(2 (sqrt 5 - sqrt 3))`

`= (sqrt 6(sqrt 3 - sqrt 2))/(sqrt 3 - sqrt 2) - (sqrt 3(sqrt 10 - sqrt 6))/(2 (sqrt 5 - sqrt 3))`

`= sqrt 6 - sqrt 3/2`