Theo viet có:\(\left\{{}\begin{matrix}x_1+x_2=-7\\x_1x_2=5\end{matrix}\right.\)
Có \(x_1^2+1+x_2^2+1=\left(x_1+x_2\right)^2-2x_1x_2+2=\left(-7\right)^2-2.5+2=41\)
\(\left(x_1^2+1\right)\left(x_2^2+1\right)=x_1^2x_2^2+x_1^2+x_2^2+1=5^2+40=65\)
\(\Rightarrow\left(x_1^2+1\right);\left(x_2^2+1\right)\) là nghiệm của pt: \(t^2-41t+65=0\)