Bài 5:
a: Ta có: \(2^x=16\)
nên x=4
b: Ta có: \(3^x=243\)
nên x=5
\(a,9^2.3^5=3^4.3^5=3^9\)
\(b,2^5.4^2.16=2^5.2^4.2^4=2^{13}\)
\(c,9^2.27.3^5=3^4.3^3.3^5=3^{12}\)
\(d,5^2.25^2.125=5^2.5^4.5^3=5^9\)
\(e,7^4.343.49^2=7^4.7^3.7^4=7^{11}\)
\(f,100^2.10^5.1000=10^{13}\)