Question

giải pt

\(\sqrt{\left(2x-1\right)^2}+\sqrt{9\left(2x-1\right)^2}=8\)\(8\)

Answer 1

\(\sqrt{\left(2x-1\right)^2}+\sqrt{9\left(2x-1\right)^2}=8\)

\(\left|2x-1\right|+3.\left|2x-1\right|=8\)

\(2x-1+6x-3=8\)

\(8x-4=8\)

\(8x=12\)

\(x=\frac{3}{2}\)

vậy \(x=\frac{3}{2}\)

Answer 2

bằng 8 nha các bạn k phải 88 đâu

Answer 3

Chị Despacito làm thiếu trường hợp rồi, \(x=1\)nữa

Answer 4

\(\left|2x-1\right|+3\left|2x-1\right|=8\)

\(2x-1+6x-3=8\)

\(8x-4-8=0\)

\(8x-12=0\)

\(8\left(x-\frac{3}{2}\right)=0\)

\(\Rightarrow x-\frac{3}{2}=0\)

\(\Rightarrow x=\frac{3}{2}\)

vậy \(x=\frac{3}{2}\)