Question

Giải phương trình:

a.2x+x-3=5

b.3(2-x)-(x+2)=0

Answer 1

a: =>3x=8

hay x=8/3

b: =>6-3x-x-2=0

=>-4x+4=0

hay x=1

Answer 2

\(a,2x+x-3=5\\ \Rightarrow3x=5+3\\ \Rightarrow3x=8\\ \Rightarrow x=\dfrac{8}{3}\\ b,3\left(2-x\right)-\left(x+2\right)=0\\ \Rightarrow6-3x-x-2=0\\ \Rightarrow4-4x=0\\ \Rightarrow4x=4\\ \Rightarrow x=1\)

Answer 3

a,2x+x-3=5

   3x-3=5

=>x=\(\dfrac{8}{3}\)

b.3(2-x)-(x+2)=0

  6-3x-x-2=0

  4-4x=0

 =>x=1