\(\sqrt{2}.x-\sqrt{50}=0\)
\(\Rightarrow\sqrt{2}\left(x-\sqrt{25}\right)=0\)
\(\Rightarrow x-5=0\)
=> x=5
\(\sqrt{2x}-\sqrt{50}=0\)
\(\Leftrightarrow\sqrt{2x}=\sqrt{50}\)
\(\Leftrightarrow x=\frac{\sqrt{50}}{\sqrt{2}}\)
\(\Leftrightarrow x=\sqrt{\frac{50}{2}}\)
\(\Leftrightarrow x=\sqrt{25}\)
\(\Leftrightarrow x=5\)
\(\sqrt{2}x-\sqrt{50}=0\Leftrightarrow\sqrt{2}x=\sqrt{50}\Leftrightarrow x=5\)
a) \(\sqrt{2}.x-\sqrt{50}=0\)
\(\Rightarrow\sqrt{2}.x=\sqrt{50}\)
\(\Rightarrow x=\frac{\sqrt{50}}{\sqrt{2}}\)
\(\Rightarrow x=\sqrt{25}\)
\(\Rightarrow x=5\)
Vậy x = 5
