ĐKXĐ: x<>1; y<>-1
\(\left\{{}\begin{matrix}\dfrac{3y}{x-1}+\dfrac{2x}{y+1}=3\\\dfrac{2y}{x-1}-\dfrac{5x}{y+1}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{15y}{x-1}+\dfrac{10x}{y+1}=15\\\dfrac{4y}{x-1}-\dfrac{10x}{y+1}=4\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{15y}{x-1}+\dfrac{10x}{y+1}+\dfrac{4y}{x-1}-\dfrac{10x}{y+1}=15+4\\\dfrac{2y}{x-1}-\dfrac{5x}{y+1}=2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{19y}{x-1}=19\\\dfrac{5x}{y+1}=\dfrac{2y}{x-1}-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{y}{x-1}=1\\\dfrac{5x}{y+1}=2\cdot1-2=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=0\\y=x-1=0-1=-1\end{matrix}\right.\left(nhận\right)\)
