Các câu hỏi tương tự
Giải hệ phương trình sau:
a. \(\left\{{}\begin{matrix}\dfrac{x+2}{y}=\dfrac{x+1}{y-2}\\\dfrac{5x+1}{5x-2}=\dfrac{y-2}{y+2}\end{matrix}\right.\)
b. \(\left\{{}\begin{matrix}2x+\left|y\right|=4\\4x-3y=1\end{matrix}\right.\)
26 tháng 11 2023 lúc 15:22
Giải hpta)left{{}begin{matrix}dfrac{4}{2x-3y}+dfrac{5}{3x+y}-2dfrac{3}{3x+y}-dfrac{5}{2x-3y}21end{matrix}right.b)left{{}begin{matrix}dfrac{7}{x-y+2}-dfrac{5}{x+y-1}dfrac{9}{2}dfrac{3}{x-y+2}+dfrac{2}{x+y-1}4end{matrix}right.c)left{{}begin{matrix}dfrac{3}{2x-y}-dfrac{6}{x+y}-1dfrac{1}{2x-y}-dfrac{1}{x+y}0end{matrix}right.d)left{{}begin{matrix}dfrac{4}{x+y-1}-dfrac{5}{2x-y+3}dfrac{5}{2}dfrac{3}{x+y-1}+dfrac{1}{2x-y+3}dfrac{7}{5}end{matrix}right.e)left{{}begin{matrix}dfrac{6}{x-2y}+dfrac{2}{x+2y}3d...
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Giải hpt
a)\(\left\{{}\begin{matrix}\dfrac{4}{2x-3y}+\dfrac{5}{3x+y}=-2\\\dfrac{3}{3x+y}-\dfrac{5}{2x-3y}=21\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{7}{x-y+2}-\dfrac{5}{x+y-1}=\dfrac{9}{2}\\\dfrac{3}{x-y+2}+\dfrac{2}{x+y-1}=4\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\dfrac{3}{2x-y}-\dfrac{6}{x+y}=-1\\\dfrac{1}{2x-y}-\dfrac{1}{x+y}=0\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{4}{x+y-1}-\dfrac{5}{2x-y+3}=\dfrac{5}{2}\\\dfrac{3}{x+y-1}+\dfrac{1}{2x-y+3}=\dfrac{7}{5}\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}\dfrac{6}{x-2y}+\dfrac{2}{x+2y}=3\\\dfrac{3}{x-2y}+\dfrac{4}{x+2y}=-1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\dfrac{1}{2x-y}+x+3y=\dfrac{3}{2}\\\dfrac{4}{2x-y}-5\left(x+3y\right)=-2\end{matrix}\right.\)
GIẢI HỘ AHHHHHHHHHH
\(\left\{{}\begin{matrix}\dfrac{x}{y}+\dfrac{2y}{x}=3\\2x^2-3y=-1\end{matrix}\right.\)
Giải các hệ phương trình sau:
a) \(\left\{{}\begin{matrix}2\left(x+1\right)-3y=-10\\3x+2y+5=0\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{x+1}{2}-\dfrac{y-2}{3}=1\\4x+3y=1\end{matrix}\right.\)
Giải pt:\(\left\{{}\begin{matrix}x-2y+\dfrac{1}{2x+3y}=2\\2x-4y+\dfrac{3}{2x+3y}=3\end{matrix}\right.\)
Giúp mk vs ạ!
GIẢI HỆ PHƯƠNG TRÌNH: \(\left\{{}\begin{matrix}\dfrac{2x-y}{3}=x+y+1\\X-3y-5=\dfrac{2x-y}{2}\end{matrix}\right.\)
Giải hệ pt sau = phương pháp thế:
a, \(\left\{{}\begin{matrix}\dfrac{x}{2}-\dfrac{y}{3}=1\\5x-8y=3\end{matrix}\right.\)
b, \(\left\{{}\begin{matrix}3x+2y=2\\6x-3y=18\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\dfrac{4}{2x-1}+\dfrac{1}{3y-2}=5\\\dfrac{1}{2x-1}-\dfrac{2}{3y-2}=-1\end{matrix}\right.\)