Question

 

\(\dfrac{x^2-2x+1}{3x-3}\)

Answer 1

\(=\dfrac{\left(x-1\right)^2}{3\left(x-1\right)}=\dfrac{x-1}{3}\)

Answer 2

\(\dfrac{x^2-2x+1}{3x-3}=\dfrac{\left(x-1\right)^2}{3\left(x-1\right)}=\dfrac{x-1}{3}\)

Answer 3

\(ĐK:x\ne1\\ \dfrac{x^2-2x+1}{3x-3}=\dfrac{\left(x-1\right)^2}{3\left(x-1\right)}=\dfrac{\left(x-1\right)\left(x-1\right)}{3\left(x-1\right)}=\dfrac{x-1}{3}\)

Áp dụng HĐT : \(a^2-2ab+b^2=\left(a-b\right)^2\)