=>-11x+33=25-10x
=>-x=-8
hay x=8
\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\\ \Rightarrow-11\left(x-3\right)=5\left(5-2x\right)\\ \Rightarrow33-11x=25-10x\\ \Rightarrow25-10x-33+11x=0\\ \Rightarrow x-8=0\\ \Rightarrow x=8\)
\(\dfrac{x-3}{5}=\dfrac{5-2x}{-11}\)
\(\Rightarrow-11.\left(x-3\right)=5.\left(5-2x\right)\)
\(\Rightarrow-11x+33=25-10x\)
\(\Rightarrow-11x+10x=25-33\)
\(\Rightarrow-1x=-8\)
\(\Rightarrow x=\left(-8\right):\left(-1\right)=8\)