Question

\(\dfrac{x-1}{15}+\dfrac{x-2}{10}+\dfrac{x-3}{5}=1\)

Answer 1

\(\dfrac{x-1}{15}+\dfrac{x-2}{10}+\dfrac{x-3}{5}=1\)

\(\Leftrightarrow2\left(x-1\right)+3\left(x-2\right)+6\left(x-3\right)=30\)

\(\Leftrightarrow2x-2+3x-6+6x-18=30\)

\(\Leftrightarrow11x=56\Rightarrow x=\dfrac{56}{11}\)

Answer 2

Ta có: \(\dfrac{x-1}{15}+\dfrac{x-2}{10}+\dfrac{x-3}{5}=1\)

\(\Leftrightarrow\dfrac{2\left(x-1\right)}{30}+\dfrac{3\left(x-2\right)}{30}+\dfrac{6\left(x-3\right)}{30}=\dfrac{30}{30}\)

\(\Leftrightarrow2x-2+3x-6+6x-18=30\)

\(\Leftrightarrow12x=56\)

hay \(x=\dfrac{14}{3}\)

Vậy: \(x=\dfrac{14}{3}\)