ĐKXĐ:\(\left\{{}\begin{matrix}x\ne0\\x\ne-3\end{matrix}\right.\)
\(\dfrac{80}{x}-\dfrac{80}{x+3}=\dfrac{3}{20}\\ \Leftrightarrow80\left(\dfrac{1}{x}-\dfrac{1}{x+3}\right)=\dfrac{3}{20}\\ \Leftrightarrow\dfrac{x+3-x}{x\left(x+3\right)}=\dfrac{3}{1600}\\ \Leftrightarrow\dfrac{3}{x^2+3x}=\dfrac{3}{1600}\\ \Leftrightarrow3x^2+9x=4800\\ \Leftrightarrow x^2+3x-1600=0\\\)
Nghiệm xấu lắm bạn
\(\dfrac{3}{20}\)x\(\dfrac{7}{16}\)+\(\dfrac{3}{20}\)x\(\dfrac{5}{16}\)+\(\dfrac{3}{20}\)\(\dfrac{3}{10}\)
Tìm x, biết:
a) \(\dfrac{3}{4}x\) - \(\dfrac{7}{12}\) = \(\dfrac{5}{6}\) - \(\dfrac{2}{3}\)
b) -\(\dfrac{5}{x}\) = \(\dfrac{20}{28}\)
c) \(2\dfrac{1}{3}\) : x = 7
d) \(\dfrac{-105}{12}\) < x < \(\dfrac{20}{7}\)
Tìm y là số nguyên :
\(y\dfrac{5}{y}=\dfrac{86}{y}\) (\(y\dfrac{5}{y}\) là hỗn số)
tìm x :
a, x . \(\dfrac{-5}{8}\) = \(\dfrac{15}{32}\) b, \(\dfrac{3}{10}\) : x =\(\dfrac{-9}{20}\)
c, \(\dfrac{-1}{4}\) x + \(\dfrac{4}{5}\) =\(\dfrac{3}{4}\) d, \(\dfrac{-7}{8}\) + \(\dfrac{2}{3}\) :x = \(\dfrac{3}{5}\) . \(\dfrac{-5}{12}\)
Tìm x, biết:
a) \(\left(3\dfrac{1}{2}-2.x\right).3\dfrac{1}{3}=7\dfrac{1}{3}\)
b) \(\dfrac{4}{9}.x=\dfrac{9}{8}-0,125\)
c) \(\dfrac{-X}{21}=\dfrac{20}{7}\)
\(A) x +\dfrac{1 }{3 } = \dfrac{2 }{5 }-\dfrac {(-1) }{3} B) \dfrac{5 }{8 } - x = \dfrac{-3 }{20 } - \dfrac{(-1 )}{6 }\)
a) x + \(\dfrac{2}{5}\) = \(\dfrac{1}{2}\)
b) x - \(\dfrac{2}{5}\) = \(\dfrac{2}{7}\)
c) \(\dfrac{3}{5}\) - x = \(\dfrac{1}{10}\)
d) x . \(\dfrac{3}{4}\) = \(\dfrac{9}{20}\)
e) x : \(\dfrac{1}{7}\) = 14
f) ( \(\dfrac{1}{4}\) + x ) . \(\dfrac{1}{2}\) = \(\dfrac{2}{5}\)
g) x . \(\dfrac{2}{3}\) - \(\dfrac{2}{3}\) = \(\dfrac{9}{12}\)
h) \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) : x = \(\dfrac{2}{5}\)
k) \(3\dfrac{4}{5}\) - x = \(\dfrac{18}{5}\)
l) x . \(2\dfrac{1}{3}\) = \(\dfrac{3}{4}\)
m) x . \(\dfrac{6}{11}\) + x . \(\dfrac{5}{11}\) = 2025
n) x . \(\dfrac{14}{9}\) - x . \(\dfrac{7}{9}\) + x . \(\dfrac{5}{9}\) = 2
Các bạn làm theo cách bình thường ở lớp 5 cho mính nhé!
Chú ý: dấu "." là dấu nhân.
\(\text{Tìm x, biết:}\)
\(a\)) \(20\text{%}x-x+\dfrac{1}{5}=\dfrac{3}{4}\)
\(b\)) \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(c\)) \(\left(x-\dfrac{3}{4}\right)\left(4+3x\right)=0\)
\(d\)) \(x-\dfrac{1}{3}x+\dfrac{1}{5}x=\dfrac{-26}{5}\)
\(e\)) \(50\text{%}x+\dfrac{2}{3}x=x-5\)
\(g\)) \(\dfrac{2}{3}\left(x+\dfrac{9}{5}\right)-\dfrac{3}{10}.\left(5x-\dfrac{1}{3}\right)=\dfrac{7}{15}\)
\(\left(-3\right).\dfrac{-5}{9}\)
\(\dfrac{-12}{5}-x=\dfrac{-3}{5}\)
\(\dfrac{-20}{x}=\dfrac{-3}{5}\)
Ghi kq thoi cx dc 
