Question

\(A) x +\dfrac{1 }{3 } = \dfrac{2 }{5 }-\dfrac {(-1) }{3} B) \dfrac{5 }{8 } - x = \dfrac{-3 }{20 } - \dfrac{(-1 )}{6 }\)

Answer 1

\(a,x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{\left(-1\right)}{3}\)

\(x+\dfrac{1}{3}=\dfrac{2}{5}+\dfrac{1}{3}\)

\(x=\dfrac{2}{5}+\dfrac{1}{3}-\dfrac{1}{3}\)

\(x=\dfrac{2}{5}\)

\(---\)

\(b,\dfrac{5}{8}-x=\dfrac{-3}{20}-\dfrac{\left(-1\right)}{6}\)

\(\dfrac{5}{8}-x=\dfrac{-3}{20}+\dfrac{1}{6}\)

\(\dfrac{5}{8}-x=\dfrac{-9}{60}+\dfrac{10}{60}\)

\(\dfrac{5}{8}-x=\dfrac{1}{60}\)

\(x=\dfrac{5}{8}-\dfrac{1}{60}\)

\(x=\dfrac{75}{120}-\dfrac{2}{120}\)

\(x=\dfrac{73}{120}\)

#\(Toru\)