\(=\dfrac{5\cdot1\cdot\left(-4\right)\cdot7}{14\cdot3\cdot15\cdot5}=\dfrac{\left(-4\right)}{2\cdot3\cdot15}=\dfrac{-4}{90}=-\dfrac{2}{45}\)
\(\dfrac{5}{14}.\dfrac{1}{3}.\dfrac{-4}{15}:\dfrac{5}{7}=\dfrac{5}{14}.\dfrac{1}{3}.\dfrac{-4}{15}.\dfrac{7}{5}=\left(\dfrac{5}{14}.\dfrac{7}{5}\right).\left(\dfrac{1}{3}.\dfrac{-4}{15}\right)=\dfrac{1}{2}.\dfrac{-4}{45}=\dfrac{-2}{45}\)