Question

\(\dfrac{2\sqrt{x-3}}{\sqrt{x-2}}=3\)

Answer 1

\(\dfrac{2\sqrt{x-3}}{\sqrt{x-2}}=3\left(x\ge3\right)\)

\(=>2\sqrt{x-3}=3\sqrt{x-2}\)

\(< =>\left(2\sqrt{x-3}\right)^2=\left(3\sqrt{x-2}\right)^2\)

\(< =>4\cdot\left(x-3\right)=9\left(x-2\right)\)

\(< =>4x-12=9x-18\\ < =>4x-9x=-18+12\\ < =>-5x=-6\\ < =>x=\dfrac{6}{5}\left(ktm\right)\)

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Answer 2

ĐKXĐ: `x>=3`

`pt<=>2sqrt(x-3)=3sqrt(x-2)`

`=>4(x-3)=9(x-2)`

`<=>5x=10`

`<=>x=2(KTM)`

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Answer 3

ĐKXĐ: `x>=3`

`pt<=>2sqrt(x-3)=3sqrt(x-2)`

`=>4(x-3)=9(x-2)`

`<=>5x=6`

`<=>x=6/5(KTM)`

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