Question

\(\dfrac{23+x}{40+x}\text{=}\dfrac{3}{4}\)

Answer 1

`(23+x)/(40+x)=3/4(x ne -40)`

`=>4(23+x)=3(40+x)`

`=>92+4x=120+3x`

`=>4x-3x=120-92`

`=>x=28`

Vậy `x=28`

Answer 2

\(\dfrac{23+x}{40+x}=\dfrac{3}{4}\) 

\(\Rightarrow4.\left(23+x\right)=3.\left(40+x\right)\) 

         \(92+4x=120+3x\) 

         \(4x-3x=120-92\) 

                 \(1x=28\) 

                   \(x=28:1\) 

                   \(x=28\)

Answer 3

28

Answer 4

28

Answer 5

28

Answer 6

28

 

Answer 7

x=28