Question

\(\dfrac{1}{8}-\dfrac{1}{2}+(\dfrac{-11}{12}+1)\)

\(\dfrac{3}{5}-\dfrac{-7}{10}+\dfrac{-13}{10}\)

Answer 1

`1/8 -1/2 + (-11/12 + 1)`

`=1/8 -1/2 + (-11/12 +12/12)`

`=1/8 -1/2 + 1/12`

`= 1/8- 4/8+1/12`

`= -3/8 + 1/12`

`=-7/24`

`---------`

`3/5 -(-7/10) + (-13/10)`

`= 3/5 + 7/10 + (-13/10)`

`= 6/10 + 7/10 + (-13/10)`

`= 13/10 +(-13/10)`

`= 0/10=0`

Answer 2

\(\dfrac{1}{8}-\dfrac{1}{2}+\left(\dfrac{-11}{12}+1\right)\\ =\dfrac{-3}{8}+\dfrac{1}{12}\\ =\dfrac{-7}{24}\\ \dfrac{3}{5}-\dfrac{-7}{10}+\left(-\dfrac{13}{10}\right)\\ =\dfrac{13}{10}-\dfrac{13}{10}\\ =0\)

Answer 3

\(\dfrac{1}{8}-\dfrac{1}{2}+\left(\dfrac{-11}{12}+1\right)=\dfrac{-3}{8}+\dfrac{1}{12}=\dfrac{-7}{24}\)

\(\dfrac{3}{5}-\dfrac{-7}{10}+\dfrac{-13}{10}=\dfrac{6}{10}-\dfrac{-7}{10}+\dfrac{-13}{10}=\dfrac{13}{10}+\dfrac{-13}{10}=\dfrac{0}{10}=0\)