Question

\((\dfrac{-1}{2})^2:\sqrt{\dfrac{9}{16}}+(\dfrac{19}{2022})^0-\sqrt{(-5)^2}\)

Answer 1

\(\left(-\dfrac{1}{2}\right)^2:\sqrt{\dfrac{9}{16}}+\left(\dfrac{19}{2022}\right)^0-\sqrt{\left(-5\right)^2}\)

`=` \(\dfrac{1}{4}:\dfrac{3}{4}+1-5\)

`=1/4 xx 4/3 + 1-5`

`=1/3+1-5`

`=1/3+3/3-15/3`

`=(1+3-15)/3`

`=(-11)/3`

Answer 2

\(=\dfrac{1}{4}:\dfrac{3}{4}+1-5=\dfrac{1}{4}.\dfrac{4}{3}+1-5=\dfrac{1}{3}+1-5=\dfrac{1}{3}+\dfrac{3}{3}-\dfrac{15}{3}=\dfrac{1+3-15}{3}=-\dfrac{11}{3}\)

Answer 3