ĐK: n nguyên dương
\(3^{n+2}-2^{n+2}+3^n-2^n\\ =\left(3^n.3^2+3^n\right)-\left(2^n.2^2+2^n\right)\\ =3^n.\left(9+1\right)-2^n.\left(4+1\right)\\ =3^n.10-2^n.5\\ =3^n.10-2^{n-1}.10\\ =10.\left(3^n-2^{n-1}\right)\)
Vì n nguyên dương nên \(3^n-2^{n-1}\in\mathbb{Z}\)
\(\Rightarrow10.\left(3^n-2^{n-1}\right)⋮10\)
hay \(3^{n+2}-2^{n+2}+3^n-2^n⋮10\) (đpcm)