AB/AC=3/4
=>HB/HC=9/16
=>HB=9/16HC
Ta có: \(AH^2=HB\cdot HC\)
\(\Leftrightarrow HC^2\cdot\dfrac{9}{16}=24^2\)
\(\Leftrightarrow HC=32\left(cm\right)\)
=>HB=18(cm)
=>BC=50(cm)
\(S_{ABC}=\dfrac{BC\cdot AH}{2}=\dfrac{50\cdot24}{2}=25\cdot24=600\left(cm^2\right)\)