Trong \(\Delta ADC\) có \(K;I;B\) thẳng hàng
\(\Rightarrow\dfrac{AK}{CK}.\dfrac{ID}{AI}.\dfrac{BC}{BD}=1\)
\(\Rightarrow\dfrac{AK}{CK}.\dfrac{1}{4}.\dfrac{6}{5}=1\)
\(\Rightarrow\dfrac{AK}{CK}=\dfrac{10}{3}\Rightarrow\dfrac{CK}{AK}=\dfrac{3}{10}=0,3\)
\(\Rightarrow\overrightarrow{CK}=-0,3\overrightarrow{AK}\)
\(\Rightarrow m=-0,3\)