a: \(=x^3-8-6x^2+12x=\left(x-2\right)^3\)
b: \(=25-4x^2+5x+4x^2-25-20x=-15x\)
c: \(=4x^2+4x+1-4x^2+4x-1=8x\)
d: \(=x^3+125-10x^2-50x-x^3=-10x^2-50x+125\)
Lời giải:
a.
$(x-2)(x^2+2x+4)-6x^2+12=(x-2)(x^2+2x+4)-6x(x-2)$
$=(x-2)(x^2+2x+4-6x)=(x-2)(x^2-4x+4)=(x-2)(x-2)^2=(x-2)^3$
b.
$(2x+5)(5-2x)+(x-5)(5+4x)=-(2x+5)(2x-5)+(4x+5)(x-5)$
$=-(4x^2-25)+(4x^2-15x-25)$
$=-4x^2+25+4x^2-15x-25=4x^2$
c.
$4x^2+4x+1-(2x-1)^2=(2x+1)^2-(2x-1)^2=(2x+1-2x+1)(2x+1+2x-1)$
$=2.4x=8x$
d.
$(x+5)(x^2+5x+25)-10x(x+5)-x^3$
$=(x+5)(x^2+5x+25-10x)-x^3$
$=(x+5)(x^2-5x+25)-x^3$
$=x^3+5^3-x^3=125$