a) \(\left(x+3\right)^3=64\)
\(\Leftrightarrow\left(x+3\right)^3=4^3\)
\(\Leftrightarrow x+3=4\)
\(\Leftrightarrow x=1\)
b) \(x^3-6x^2+12x-2=14\)
\(\Leftrightarrow x^3-6x^2+12x-8+6=14\)
\(\Leftrightarrow x^3-3x^2.2+3x.2^2-2^3=8\)
\(\Leftrightarrow\left(x-2\right)^3=8\)
\(\Leftrightarrow\left(x-2\right)^3=2^3\)
\(\Leftrightarrow x-2=2\)
\(\Leftrightarrow x=4\)
`(x + 3)^3 = 64`
`=>( x + 3)^3 = 4^3`
`=> x + 3 = 4`
`=> x = 4-3`
`=> x = 1`
Vậy `x = 1`
`x^3 - 6x^2 + 12x - 2 = 14`
`=> x^3 - 3*x^3*2 + 3*x*2^2 - 2^3 + 6 = 14`
`=> (x - 2)^3 + 6 = 14`
`=>(x-2)^3 = 8`
`=> (x-2)^3 = 2^3`
`=> x - 2 = 2`
`=> x = 2 + 2`
`=> x = 4`
Vậy `x = 4`
