Question

bài 1 ; 6x(x+2018)-3(x+2018)=0

bài 2; x(x-11)+3(11-x)=0

bài 3; x(x-3)-2(3-x)=0

bài 4; 2x(x+5)-4(x+5)=0

mấy bạn giúp mình với ạ

Answer 1

1: =>(x+2018)(6x-3)=0

=>x+2018=0 hoặc 6x-3=0

=>x=1/2 hoặc x=-2018

2: x(x-11)+3(11-x)=0

=>(x-11)(x-3)=0

=>x=11 hoặc x=3

4: =>(x+5)(2x-4)=0

=>2x-4=0 hoặc x+5=0

=>x=2 hoặc x=-5

3: =>(x-3)(x+2)=0

=>x=3 hoặc x=-2

Answer 2

Bài 1:

\(6x\left(x+2018\right)-3\left(x+2018\right)=0\)

\(\Leftrightarrow\left(x+2018\right)\left(6x-3\right)=0\)

\(\Leftrightarrow3\left(x+2018\right)\left(2x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2018\\2x=1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2018\\x=\dfrac{1}{2}\end{matrix}\right.\)

Bài 2:

\(x\left(x-11\right)+3\left(11-x\right)=0\)

\(\Leftrightarrow x\left(x-11\right)-3\left(x-11\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-11\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=11\end{matrix}\right.\)

Câu 3:

\(x\left(x-3\right)-2\left(3-x\right)=0\)

\(\Leftrightarrow x\left(x-3\right)+2\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)

Câu 4:

\(2x\left(x+5\right)-4\left(x+5\right)=0\)

\(\Leftrightarrow\left(x+5\right)\left(2x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\2x=4\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)