a) x2 + 4y2 + 4xy – 16
= (x + 2y)2 -16
= (x + 2y – 4)(x + 2y + 4).
b) 5x2 - 10xy + 5y22
= 5(x2 - 2xy + y2)
= 5(x - y)2
a)x^2 + 4y^2 + 4xy - 16 = (x^2 + 4xy + 4y^2) - 16 = (x + 2y)^2 - 16 = (x + 2y - 4)(x + 2y + 4)
Vậy...
b)5x^2 - 10xy + 5y^2 = 5(x^2 - 2xy + y^2) = 5(x - y)^2
Vậy...
a).
<=> \(x^2+4xy+\left(2y\right)^2-4^2\)
<=> \(\left(x+2y\right)^2-4^2=\left(x+2y+4\right)\left(x+2y-4\right)\)
a) x2 + 4y2 + 4xy – 16
= (x + 2y)2 -16
= (x + 2y – 4)(x + 2y + 4)
b) 5x2 - 10xy + 5y22
= 5 (x2 - 2xy + y2)
= 5 (x - y)2
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