Question

B= \(\dfrac{\dfrac{2}{3}\times\dfrac{17}{3}-\dfrac{2}{3}\times\dfrac{4}{13}+\dfrac{7}{3}}{\dfrac{9}{2}-\dfrac{9}{4}-\dfrac{9}{5}}\)

Giải hộ với ạ!

Answer 1

\(B=\dfrac{\dfrac{2}{3}\left(\dfrac{17}{3}-\dfrac{4}{13}\right)+\dfrac{7}{3}}{\dfrac{9}{20}}=3:\dfrac{9}{20}=3\cdot\dfrac{20}{9}=\dfrac{60}{9}=\dfrac{20}{3}\)

Answer 2

\(B=\dfrac{\dfrac{2}{3}\times\left(\dfrac{17}{3}-\dfrac{4}{13}\right)+\dfrac{7}{3}}{\dfrac{9}{2}-\dfrac{9}{4}-\dfrac{9}{5}}=\dfrac{\dfrac{2}{3}\times1+\dfrac{7}{3}}{\dfrac{9.10-9.5-9.4}{20}}\\ =\dfrac{\dfrac{2}{3}+\dfrac{7}{3}}{\dfrac{90-45-36}{20}}=\dfrac{\dfrac{9}{3}}{\dfrac{9}{20}}=\dfrac{9}{3}\times\dfrac{20}{9}=\dfrac{20}{3}\)