Question

b) 5.[225-(x-10)]-125=0

Answer 1

\(b,5\left[225-\left(x-10\right)\right]=125\\ 225-\left(x-10\right)=125:5\\ 225-\left(x-10\right)=25\\ x-10=225-25\\ x-10=200\\ x=200+10\\ x=210\)

Answer 2

=>5(225-x+10)=125

=>235-x=25

=>x=210

Answer 3

b) 5 . [225 - (x - 10)] - 125 = 0
5 . [225 - (x - 10)] = 0 + 125
5 . [225 - (x - 10)] = 125
[225 - (x - 10)] = 125 : 5
[225 - (x - 10)] = 25
(x - 10) = 225 - 25
(x - 10) = 200
x = 200 + 10
x = 210.

Answer 4

b,5[225−(x−10)]=125225−(x−10)=125:5225−(x−10)=25x−10=225−25x−10=200x=200+10x=210