\(=5\sqrt{2}-\dfrac{3}{2}\cdot4\sqrt{2}-\dfrac{1}{3}\cdot6\sqrt{2}+8=-3\sqrt{2}+8\)
Đúng 1
Bình luận (1)
Các câu hỏi tương tự
tính
A=\(\left(1-\sqrt{7}\right).\dfrac{\sqrt{7}+7}{2\sqrt{7}}\)
B=\(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)
C=\(\sqrt{32}-\sqrt{50}+\sqrt{18}\)
D=\(\sqrt{72}+\sqrt{4\dfrac{1}{2}}-\sqrt{32}-\sqrt{162}\)
E=\(\dfrac{1}{2}\sqrt{48}-2\sqrt{75}-\dfrac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\dfrac{1}{3}}\)
a
\(\sqrt{32}\)+\(\sqrt{50}\) - 2\(\sqrt{200}\) + 3\(\sqrt{72}\)
b)\(\dfrac{3}{\sqrt{ }2-1}\) + \(\sqrt{\left(3-\sqrt{2}\right)^{^2}}\) - 2\(\sqrt{2}\)
rút gọn các biểu thức trên
a, \(\sqrt{200}-\sqrt{32}+\sqrt{72}\)
b, \(4\sqrt{20}-3\sqrt{125}+5\sqrt{45}-15\sqrt{\dfrac{1}{5}}\)
c, \(\left(2\sqrt{8}+3\sqrt{5}-7\sqrt{2}\right)\left(72-5\sqrt{20}-2\sqrt{2}\right)\)
a,(\(\left(\sqrt{50}-\sqrt{32}+\sqrt{8}\right):\sqrt{2}\) b,\(\dfrac{4}{\sqrt{5}-1}-5\sqrt{\dfrac{1}{5}}\)
6) (3\(\sqrt{2}\) -\(\sqrt{3}\))(\(\sqrt{3}\)+3\(\sqrt{2}\))
7) \(\sqrt{72}\)+\(\sqrt{4\dfrac{1}{2}}\) - \(\sqrt{32}\) - \(\sqrt{162}\)
\(\left(4\sqrt{8}-\sqrt{72}+5\sqrt{\dfrac{1}{2}}\right)2\sqrt{2}\)
\(\dfrac{5+\sqrt{5}}{\sqrt{5}}+\dfrac{3+\sqrt{3}}{\sqrt{3}+1}\left(\sqrt{3}+\sqrt{5}\right)\)
1 Tính
a \(\sqrt{36}-\sqrt{100}\)
b Tìm x để biểu thức \(\sqrt{\dfrac{2}{2x-1}}\) có nghĩa
2 Thực hiện phép tính
a) A = \(\left(15\sqrt{180}-5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
b) B = \(\sqrt{32}-\sqrt{50}-16\sqrt{\dfrac{1}{8}}\)
Tính: a, \(\left(4\sqrt{2}-\dfrac{11}{2}\sqrt{8}-\dfrac{1}{3}\sqrt{288}+\sqrt{50}\right)\left(\dfrac{1}{2}\sqrt{2}\right)\)
b, \(\left(\dfrac{4}{5}\sqrt{5}-\dfrac{1}{3}\sqrt{\dfrac{1}{5}}+3\sqrt{20}+\dfrac{1}{2}\sqrt{245}\right)\div\sqrt{5}\)
\(c\sqrt{20}-\sqrt{45}+3\sqrt{8}+\sqrt{72}\)
\(d.\dfrac{3}{\sqrt{3}+1}\)
\(f.\dfrac{2}{\sqrt{10}+\sqrt{7}}\)