\(MH^2=AM.MB\) (tam giác vuông AHB)
\(\Rightarrow\dfrac{1}{AM.MB}=\dfrac{1}{MH^2}=\dfrac{1}{AH^2}+\dfrac{1}{HB^2}\left(1\right)\)
\(AH^2=AN.AC\) (tam giác vuông AHC)
\(\Rightarrow\dfrac{1}{AH^2}=\dfrac{1}{AN.AC}\left(2\right)\)
\(\left(1\right);\left(2\right)\Rightarrow\dfrac{1}{AM.MB}=\dfrac{1}{AN.AC}+\dfrac{1}{HB^2}\)
Bạn xem lại đề \(AN.NC\rightarrow AN.AC\)