54.107-53 phần 53.107+54
=5725 phần 5725
->A>1
=1
B=36182 phần 36181
-> B<1
->A > b
A = 54.107-53 / 53.107+54 = (53+1).107-53 / 53.107+54
= 53.107 + 107 - 53 / 53.107+54 = 53.107+54 / 53 . 107 + 54
=> A = 1
B = 135.269-133 / 134.269+135
tính B như trên rồi so sánh
kết quả là A > B
Ta có:
\(A=\dfrac{54\cdot107-53}{53\cdot107+54}=\dfrac{53\cdot107+107-53}{53\cdot107+54}=\dfrac{53\cdot107+54}{53\cdot107+54}=1\)
\(B=\dfrac{135\cdot269-133}{134\cdot269+135}=\dfrac{134\cdot269+269-133}{134\cdot269+135}=\dfrac{134\cdot269+136}{134\cdot269+135}>1\)
=>A>B
Vậy A>B
Ta có : A =\(\dfrac{54.107-53}{53.107+54}=\dfrac{53.107+107-53}{53.107+54}=\dfrac{53.107+\left(107-53\right)}{53.107+54}=\dfrac{53.107+54}{53.107+54}=1\)Ta có : B = \(\dfrac{135.269-133}{134.269+135}=\dfrac{134.269+269-133}{134.269+135}=\dfrac{134.269+\left(269-133\right)}{134.269+135}=\dfrac{134.269+136}{134.269+135}=\dfrac{134.269+135}{134.269+135}+\dfrac{1}{134.269+135}=1+\dfrac{1}{134.269+135}\) => B > 1 ( vì \(\dfrac{1}{134.269+135}>0\) )
Mà A = 1
=> A < B
Vậy A < B