Question

a)  \(\dfrac{5x-2}{3}+x=1+\dfrac{5-3x}{2}\)

b)  \(\dfrac{\left(3x-1\right)\left(x+2\right)}{3}-\dfrac{2x^2+1}{2}=\dfrac{11}{2}\)

c)  \(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\)

d)  \(\dfrac{x-1}{2}+\dfrac{x-1}{3}-\dfrac{x-1}{6}=2\)

Answer 1

a, \(\Rightarrow10x-4+6x=6+15-9x\Leftrightarrow7x=25\Leftrightarrow x=\dfrac{25}{7}\)

b, \(\Rightarrow2\left(3x^2+5x-2\right)-6x^2-3=33\Leftrightarrow10x-7=33\Leftrightarrow x=4\)

c, \(\Rightarrow12x-10x-4=21-9x\Leftrightarrow11x=25\Leftrightarrow x=\dfrac{25}{11}\)

d, \(\Rightarrow3x-3+2x-2-x+1=12\Leftrightarrow4x=16\Leftrightarrow x=4\)

Answer 2

\(\dfrac{5x-2}{3}+x=1+\dfrac{5-3x}{2}\)

\(\Leftrightarrow\dfrac{5x-2+3x}{3}=\dfrac{2+5-3x}{2}\)

\(\Leftrightarrow\dfrac{8x-2}{3}=\dfrac{7-3x}{2}\)

\(\Leftrightarrow16x-4=21-9x\)

\(\Leftrightarrow16x+9x=21+4\)

\(\Leftrightarrow25x=25\)

\(\Leftrightarrow x=1\)

Answer 3

\(a,\dfrac{5x-2}{3}+x=1+\dfrac{-3x+5}{2}\)

\(2\left(5x-2\right)+6x=-9x+21\)

\(16x+9x=21+4\)

\(25x=25\)

\(x=1\)

\(b,\dfrac{3x^2+5x-2}{3}-\dfrac{2x^2+1}{2}=\dfrac{11}{2}\)

\(\dfrac{6x^2=10x-4-6x^2-3}{6}=\dfrac{11}{2}\)

\(\dfrac{10x-4-3}{6}=\dfrac{11}{2}\)

\(\dfrac{10x-7}{6}=\dfrac{11}{2}\)

\(10x=33+7\)

\(x=4\)