làm 1 mẫu
\(\left(a+b-c\right)^2=a^2+b^2+c^2+2ab-2ab-2bc\)
thôi t làm lại
\(\left(a+b-c\right)^2=a^2+b^2+c^2+2ab-2ab-2bc\)
\(a)\left(a+b-c\right)^2=\left[\left(a+b\right)-c\right]^2=\left(a+b\right)^2-2\left(a+b\right)c+c^2\) \(=a^2+2ab+b^2-2ac-2bc+c^2=a^2+b^2+c^2+2ab-2ac-2bc\)
\(b)\left(2a+b-3c\right)^2=\left[\left(2a+b\right)-3c\right]^2=\left(2a+b\right)^2-2\times3\left(2a+b\right)c+9c^2\) \(=4a^2+4ab+b^2-6\left(2a+b\right)c+9c^2=4a^2+4ab+b^2-12ac-6bc+9c^2\)
\(=4a^2+b^2+9c^2+4ab-12ac-6bc\)