a)
\(2\sqrt{16}+8\cdot\left(-\dfrac{1}{2}\right)^2\\ =2\cdot4+8\cdot\dfrac{1}{4}\\ =8+2\\ =10\)
b)
\(\dfrac{3}{4}-\dfrac{1}{4}\cdot\left(3\dfrac{1}{2}-0,5+\left|-\dfrac{1}{2}\right|\right)\\ =\dfrac{3}{4}-\dfrac{1}{4}\cdot\left(\dfrac{7}{2}-0,5+\dfrac{1}{2}\right)\\ =\dfrac{3}{4}-\dfrac{1}{4}\cdot\dfrac{7}{2}\\ =\dfrac{3}{4}-\dfrac{7}{8}\\ =-\dfrac{1}{8}\)
\(a,2\sqrt{16}+8.\left(\dfrac{-1}{2}\right)^2\\ =2.4+8.\dfrac{1}{4}\\ =8+2\\ =10\)
\(b,\dfrac{3}{4}-\dfrac{1}{4}.\left(3\dfrac{1}{2}-0,5+\left|\dfrac{-1}{2}\right|\right)\\ =\dfrac{3}{4}-\dfrac{1}{4}.\left(\dfrac{7}{2}-\dfrac{1}{2}+\dfrac{1}{2}\right)\\ =\dfrac{3}{4}-\dfrac{1}{4}.\left(\dfrac{6}{2}+\dfrac{1}{2}\right)\\ =\dfrac{3}{4}-\dfrac{1}{4}.\dfrac{7}{2}\\ =\dfrac{3}{4}-\dfrac{7}{8}\\ =\dfrac{6}{8}-\dfrac{7}{8}\\ =\dfrac{-1}{8}\)
2\(\sqrt{16}\) + 8.( \(\dfrac{-1}{2}\))2 \(\dfrac{3}{4}\) - \(\dfrac{1}{4}\).( 3\(\dfrac{1}{2}\) - 0,5 + |\(\dfrac{-1}{2}\)|
= 2.4 + 8 . \(\dfrac{1}{4}\) = \(\dfrac{3}{4}\) - \(\dfrac{1}{4}\) . ( 3,5 - 0,5 + 0,5)
= 8 + 2 = 0,75 - \(\dfrac{1}{4}\) . 3,5
= 10 = 0,75 - 0,875
= -0,125