a) \(\dfrac{2}{11}\cdot\dfrac{-5}{4}+\dfrac{-9}{11}\cdot\dfrac{5}{4}+1\dfrac{3}{4}=\dfrac{-2}{11}\cdot\dfrac{5}{4}+\dfrac{-9}{11}\cdot\dfrac{5}{4}+\dfrac{7}{4}=\dfrac{5}{4}\cdot\left(\dfrac{-2}{11}+\dfrac{-9}{11}\right)+\dfrac{7}{4}=\dfrac{5}{4}\cdot\left(-1\right)+\dfrac{7}{4}=-\dfrac{5}{4}+\dfrac{7}{4}=\dfrac{1}{2}\)